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Simplifying 5c2 + -52c + 20 = 0 Reorder the terms: 20 + -52c + 5c2 = 0 Solving 20 + -52c + 5c2 = 0 Solving for variable 'c'. Factor a trinomial. (2 + -5c)(10 + -1c) = 0Subproblem 1
Set the factor '(2 + -5c)' equal to zero and attempt to solve: Simplifying 2 + -5c = 0 Solving 2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5c = 0 + -2 -5c = 0 + -2 Combine like terms: 0 + -2 = -2 -5c = -2 Divide each side by '-5'. c = 0.4 Simplifying c = 0.4Subproblem 2
Set the factor '(10 + -1c)' equal to zero and attempt to solve: Simplifying 10 + -1c = 0 Solving 10 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1c = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1c = 0 + -10 -1c = 0 + -10 Combine like terms: 0 + -10 = -10 -1c = -10 Divide each side by '-1'. c = 10 Simplifying c = 10Solution
c = {0.4, 10}
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